The HCF of two numbers is 8 and their sum is 48. How many such pair are possible?
Answers
Answered by
0
Step-by-step explanation:
We know that H.C.F×L.C.M=product of the numbers.
Let x be the other number
⇒8×48=24×x
⇒24x=8×48
⇒x=
24
8×48
=8×2=16
∴ the other number is 16
Similar questions