The HCF of two polynomials is x+1 and their LCM is x6-1. If one of them is 3x+1, then find the other polynomial
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Step-by-step explanation:
Given
HCF=x+1
LCM=6x-1
One of the numbers is 3x+1
Let the other number be y
we know LCM×HCF=product of two numbers
(6x-1)(x+1) = (3x+1)(y)
6x^2+6x-x-1 = (3x+1)(y)
6x^2+5x-1 = (3x+1)(y)
y = 6x^2+5x-1÷3x+1
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