The hcf of two polynomials is (x + 3) and their lcm is x3 – 7x + 6. if one of the polynomials is (x2 + 2x – 3), then the other is
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Let P(x) = x² 2x – 3 = x² + 3x – x – 3 = x(x + 3) – 1(x + 3)
= (x + 3)(x – 1)
LCM = x^3 – 7x + 6 = x²(x – 1) + x(x – 1) – 6(x – 1) = (x – 1)( x² + x – 6)
Let other polynomial be Q(x),
P(x)×Q(x) = (HCF)×(LCM)
Hence, Q(x) = [(HCF)×(LCM)]/[P(x)]
= [(x + 3)×(x – 1)×( x² + x – 6)]/[±(x + 3)×(x – 1)]
= ( x²+ x – 6) [Ans.]
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