Question

the hcf of twonumber is 4andthier lcm is 40.if onenumber is 8,find the other number

Answer 1

one number=(lcm*hcf)/second number

=(4*40)/8

=160/8

=20 ans

Answer 2

LCM × HCF= product of two numbers
40×4=8× x. (x being the unknown number)
160/8= x
20 = x
Hence.... the other number is 20