Question

• The HCF of (x2 - 1)2, (x + 1), and (x2 - 1) is​

Answer 1

Answer:

{(x+1)(x-1)}2,(x+1),(x+1)(x-1)

{(x+1)(x-1)(x+1)(x-1)},(x+1),(x+1)(x-1)

HCF=(x+1)