• The HCF of (x2 - 1)2, (x + 1), and (x2 - 1) is
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{(x+1)(x-1)}2,(x+1),(x+1)(x-1)
{(x+1)(x-1)(x+1)(x-1)},(x+1),(x+1)(x-1)
HCF=(x+1)
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