Question

The HCF of x2 + 2x + 1 and x2 + 8x + 7 is…​

Answer 1

Step-by-step explanation:

Given polynomials are x²+2x+1 and x²+8x+7

x²+2x+1 can be written as

=>x²+x+x+1

=>x(x+1)+1(x+1)

=>(x+1)(x+1)

and

x²+8x+7 can be written as

=>x²+x+7x+7

=>x(x+1)+7(x+1)

=>(x+1)(x+7)

Now we have

x²+2x+1=(x+1)(x+1)

x2+8x+7=(x+1)(x+7)

The Least common factor of the given polynomials is (x+1)

HCF=(x+1)

HCF of x²+2x+1 and x²+8x+7 =(x+1)

Answer 2

well done ✔️ ✔️ ✔️ ✔️ ✔️