Hindi, asked by sportg707, 20 days ago

The HCF of x³y³y⁴ and x⁵y⁷ is . options - 1. x⁵ 2. y⁷.3.x³y⁴

Answers

Answered by riyachakravarti23

0

Explanation:

Correct option is D)

x5+2x4+x3andx7−x5

⇒x3(x2+2x+1)⇒x3(x+1)(x+1)

x7−x5⇒=x5(x2−1)⇒x5(x+1)(x−1)

∴RequiredH.C.F=x3(x+1)

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