Question

the HCF of x5y2 and x2y7​

Answer 1

Answer:

Step-by-step explanation:

since x and y are prime they cannot be factorized further

a=x5y2 and b=x2y3

1st dividing continuously by x

a/x=x4y2⇒a/x2=x3y2⇒....⇒a/x5=y2 cannot be further divided by x

for b

b/x=xy3⇒b/x2=y3  cannot be further divided by x

for a its x5 and for b its x2

HCF=x2

same for y

for a its y2 and for b its y3

HCF=y2

HCF(a,b)=x2*y2

              =x2y2

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Answer 2

Answer:

hope it help you .....

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