The head of a construction company wants to give as a bonus 4 decorated hemispherical balls to 500 workers on Diwali. The radius of hemispherical bowl is 10.5 cm . If the decoration of pattern on outer curved surface area costs Rs 5 per 100 cm² , then calculate the cost paid by head. Which value is depicted by head?
kumarysunil:
pls fast........
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area of hemisphere is 2 x pie x r to the power 2
therefore , total balls =4 x 500 = 200 balls
now , area of one ball = 2*22/7*10.5*10.5=712.8 cm2
area of 2000 balls= 2000*712.8=14,25,600cm2
therefore, cost of designing = (14,25,600*5)/100=Rs.71,280
therefore , total balls =4 x 500 = 200 balls
now , area of one ball = 2*22/7*10.5*10.5=712.8 cm2
area of 2000 balls= 2000*712.8=14,25,600cm2
therefore, cost of designing = (14,25,600*5)/100=Rs.71,280
2*22/7*0.5 *10.5 = 692.72.........
HOW YOU GOT 72.8 CMsq
and how 2000 balls?
sorry area of hemisphere =1/2*22/7*14*14
no radius is 10.5
and 4*500=2000
okk .....10.5*10.5
ok
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