The head of a crew gauge has 200 divisions. Its head advances by 1 mm for 2 complete rotations of its head. Find it's pitch and least count.
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Explanation:
Head of the screw gauge advances 1 mm for two complete rotations.
So, pitch of the screw gauge P=
2
1 mm
=0.5 mm
Number of divisions N=200
So, Least count L.C.=
N
P
=
200
0.5 mm
=0.0025 mm
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