Question

the head of a pin is a square of side 10 mm.find the pressure on it due to a force of 20 Newton ​

Answer 1

Given :

Magnitude of applied force = 20N

Side of square = 10mm

To Find :

Pressure exerted by pin.

Solution :

■ Pressure is measured as the force exerted per unit area.

• It is a scalar quantity having only magnitude.
• SI unit : N/m² or Pa

Formula : $\underline{\boxed{\bf{\orange{Pressure=\dfrac{Force}{Area}}}}}$

Therefore first of all we need to find area of the head of pin.

We know that,

• Area of square = (side)²

Side of square = 10mm = 0.01m

$:\implies\sf\:Area=(side)^2$

$:\implies\sf\:Area=(0.01)^2$

$:\implies\bf\:Area=10^{-4}\:m^2$

By substituting the values in the formula of pressure, we get

$:\implies\sf\:P=\dfrac{F}{A}$

$:\implies\sf\:P=\dfrac{20}{10^{-4}}$

$:\implies\:\underline{\boxed{\bf{\purple{P=2\times 10^5\:Pa}}}}$