Question

The head of a screw gauge is divided into 100 divisions. It advances 5 mm when the
screw is rotated through 5 rotations. Then least count is

ans is 0.001 cm process needed ​

Answer 1

Answer:

5 rotations = 5 mm

1 rotation = 5÷5 = 1 mm

In 1 rotation 100 divisions are moved

Therefore 100 divisions = 1 mm

Therefore 1 division = 1/100mm = 0.01mm =0.001cm which is by definition is least count