The head produced by a liquid of relative density
1.62 is equal to the pressure of 250 kPa. What is
the head (m) produced by the liquid?
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Given info : The head produced by a liquid of relative density 1.62 is equal to the pressure of 250 kPa.
To find : the head produced by the liquid.
Solution : head produced by liquid due to pressure is given by, h = P/ρg
Where P is pressure, ρ is density of liquid and g is acceleration due to gravity.
Here, P = 250kPa = 2,50,000 Pa
ρ = 1.62 × 10³ kg/m³ [ liquid density = relative density × density of water at 4°C]
g = 9.8 m/s²
So , h = (250000)/(1.62 × 10³ × 9.8)
= (250)/(1.62 × 9.8)
= 15.75 m
Therefore head produced in m by liquid is 15.75m
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