the heat capacity for h2o is 73.6 j/mol find the heat needed to raise the temperature of 90 gram of water from 35℃. to 65℃ ????pls ans soon
Answers
Answered by
1
Answer:
The heat capacity is. 73.6
temperature. 90
water. 35° C
73.6-90=. - 16.4
35/ 16.4= 2.134
hope it helps you u
......
Answered by
1
Explanation:
heat capacity = heat / mole × change in
temperature
C = Q/ n × temp change n = 90/18=5m
Q = C × n × (65-35)
Q = 73.6 × 5 × 30= 1040 j
Similar questions