the heat capacity of a solid of mass 175 grams is 315 joule Celsius inverse then the its specific heat capacity is
Answers
Given
Mass of Ice at -10°C = 2Kg
To Find – Quantity of heat required to completely melt the ice.
Formula
Q = mc(ΔT)
Q = mF
where m is the mass (Kg)
F is the latent heat of fusion of ice (J/kg)
c is the specific heat of ice (J/kg-K)
ΔT is the temperature difference(K)
Step 1
Heat required to change temperature of ice from -10°C to 0°C.
ΔT = Initial temperature – Final temperature
= 263K – 273K
= -10K
Q = mc(ΔT)
m = 2kg
c = 2.1 × 103 J/kg K
ΔT = -10K
Q1 = 2Kg × 2.1 × 103 J/kg K × (-10K)
Q1 = - 42 × 103 J (Negative sign shows that the heat is absorbed)
Step 2
Heat required to convert ice to water at 273K.
Q = mF
m = 2kg
F = 336 × 103 J/kg
Q2 = 2kg × 336 × 103 J/kg
Q2 = 672 × 103 J
Total heat required is Q1 + Q2 = 714 × 103 J
C': heat capacity
c :specific heat capacity
m: mass
C'= mc
315=175*c
c=315/175
c=1.8 Joules/g ℃