The heat dissipated in a resistance can be determined from the relation ------------> H = l^2 RT/4.2 cal. If the maximum errors in the measurement of current, resistance and time are 2%, 1% and 2% respectively, what would be the maximum error in the dissipated heat? correct mathematical answers gets brainliest
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H=I²RT
Answer is maximum error in dissipated heat = 7%
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H = l^2 RT/4.2 cal.
= 2*2+1+2
= 7%
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