Question

The heat dissipated in a resistance can be determined from the relation ------------> H = l^2 RT/4.2 cal. If the maximum errors in the measurement of current, resistance and time are 2%, 1% and 2% respectively, what would be the maximum error in the dissipated heat? correct mathematical answers gets brainliest please give correct answer

Answer 1

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Answer 2

ANSWER

We have,

H = I^2 × R × T

H = 2 × ∆I/I + ∆R/R + ∆T/T

Now, by putting the above values we get,

H = 2×2 + 1 + 2

H = 4 + 3

H = 7%

Hence, Maximum Error will be 7%.