Question

The heat energy required to raise the temperature of 8 gm of Ice at -10°C to
ter at 60°C​

Answer 1

ANSWER :

To find the heat energy required to raise the temp. of 8 gm of Ice at -10°C to water at 60°C :

To convert 10g of ice to steam, the following steps need to be taken into account-

o convert 10g of ice to steam, the following steps need to be taken into account-1. Ice at -10°C to Ice at 0°C:

Heat supplied during this process is sensible heat and it is given by

mc (T2-T1) = 0.01 * 2.108 * (0-(-10)) = 0.2108 kJ

'c' for ice is 2.108 kJ/kg.K

for ice is 2.108 kJ/kg.K2. Ice at 0°c to 0°c water:

e at 0°c to 0°c water:Latent heat supplied for conversion of ice to water given by

mL(fusion) = 0.01*333. 55 = 3.3355 kJ

3. Water at 0°c to water at 60°c:

mc(T2-T1) = 0.01*4.186*(60-0) = 2.5116 kJ

4. Water at 60°c to steam at 60°c:

Latent heat supply given by

mL(vaporisation) = 0.01*2260 = 22.60 kJ

Therefore total heat that's needed to be supplied is

0.2108+3.3355+22.60 = 26.1463 kJ

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