Question

the heat engine gives out 500 joules of heat energy and use full work determine the energy supplied to it as input of its efficiency is 40%​

Answer 1

Answer:

833.33 Joule

Explanation:

efficiency = W usefull/ Heat Supplied

= 1-( Heat rejected/Heat Supplied)

.4 = 1- 500/ Heat Supplied => Heat Supplied = 500/.6 = 833.33 Joule

Answer 2

Answer:

hello mate..

Explanation:

Given : For Carnot engine,

⇒T

1

=600K T

2

=300K

⇒W=800J

We know,

Efficiency (n)=1−

T

1

T

2

=

Q

W

⇒

Q

W

=1−

600

300

⇒Q=

1−

2

1

W

⇒

2

1

800

⇒Q=1600J

i.e, heat given to system is 1600J.

Hence

, the answer is 1600.

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