the heat engine gives out 500 joules of heat energy and use full work determine the energy supplied to it as input of its efficiency is 40%
Answers
Answered by
3
Answer:
833.33 Joule
Explanation:
efficiency = W usefull/ Heat Supplied
= 1-( Heat rejected/Heat Supplied)
.4 = 1- 500/ Heat Supplied => Heat Supplied = 500/.6 = 833.33 Joule
Answered by
3
Answer:
hello mate..
Explanation:
Given : For Carnot engine,
⇒T
1
=600K T
2
=300K
⇒W=800J
We know,
Efficiency (n)=1−
T
1
T
2
=
Q
W
⇒
Q
W
=1−
600
300
⇒Q=
1−
2
1
W
⇒
2
1
800
⇒Q=1600J
i.e, heat given to system is 1600J.
Hence
, the answer is 1600.
hope you get your answer
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