The heat evolved in neutralizing aqueous solution of hcn with a strong alkali is 3 kcal.The enthalpy of dissociation of hcn is
Answers
Answered by
7
It's 13.7-3 = 10.7 kilocalories is your answer.
Answered by
4
⛦Hҽɾҽ ɿʂ ү๏υɾ Aɳʂฬҽɾ⚑
▬▬▬▬▬▬▬▬▬▬▬▬☟
▶ The heat evolved in neutralizing aqueous solution of hcn with a strong alkali is 3 kcal.The enthalpy of dissociation of hcn is?
➙ 13.7 - 3
➙ 10.7 Kcal...✔
_________
Thanks...✊
▬▬▬▬▬▬▬▬▬▬▬▬☟
▶ The heat evolved in neutralizing aqueous solution of hcn with a strong alkali is 3 kcal.The enthalpy of dissociation of hcn is?
➙ 13.7 - 3
➙ 10.7 Kcal...✔
_________
Thanks...✊
Similar questions
Math,
6 months ago
Economy,
6 months ago
Physics,
1 year ago
Math,
1 year ago
Computer Science,
1 year ago