Question

The heat liberated when 1.89 g of benzoic acid is burnt in a bomb calorimeter at 25°C increases the tempraturw of 18.94 kg of water by 0.632°C. If the specific heat of water at 25°C is 0.998 cal/g-deg, the value of the heatof combustiom of benzoic acid is?
A]881.1kcal
B]771.4kcal
C]981.1kcal
D]871.2kcal

Plz answer this soon ill mark as brainlist

Answer 1

Answer:

I think option (A) 881.1kcal

Answer 2

Answer:

weight of benzoic acid = 1.89 gram

temp of bomb calorimeter= 25 degree celcius

Delta T= 0.632

specific heat of the water (s) =0.998

benzoic. acid (Q) = Ms Delta T

= 18940*0.998*0.632

= 11946.14 calories

since 1.89 gram of benzoic acid liberated 11946.14

heat liberated by 122gram of molecular mass of benzoic acid

= 11946.14*122/1.89

=77126.5cal

771.12kcal

hope it's clear to u...