the heat must be absorbed by ice of mass 500g at -10℃ to take it to water at 20℃ is (specific heat of ice 2.2 kj/kgK,specific heat of water is 4.2kj/kgK and latent heat of fusion of ice is 300kj/kg)
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Answer:
480 kj
Explanation:
Q=ml+ms(t2-t1)
=500gm{300kj/kgk+2.2kj/kg*30}
=500{300+66}
=480000
=480kj
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