The heat needed to vapourize 30 g of water at 80 C (Degree Celcius).
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Answer:
Q= 10,080 J
Explanation:
m=30g = 0.03kg.
c of water=4,200 J/kg C.
T=80 degree C(80-0=80).
Q=mcT,
Q=0.03*4,200*80,
Q=10,080 J.
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