The heat of combustion of ethylene at 17 and at constant volume is
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when a certain amount of ethylene was combusted, 6226 kj heat was evolved . if the heat of the combustion of ethylene is 1411kj/mole, the volume of oxygen that entered in to the reaction at stp is nearly
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C2H4 + 3O2 -------> 2 CO2 + 2 H2O
Moles of O2 reacted = (6226/1411) x 3
Volume of O2 entered at STP = (6226/1411) x 3 x 224 = 296.5 lit
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