Chemistry, asked by shakirainapure3137, 1 year ago

The heat of combustion of methane at 298° K is expressed by CH_{4(g)} + 2O_{2(g)} \longrightarrow CO_{2(g)} + 2H_2O and \Delta H = 890.2 kJ. Magnitude of \Delta E of reaction at this temperature is
(a) infinity
(b) equal to \Delta H
(c) less than \Delta H
(d) greater than \Delta H

Answers

Answered by purvi200428
0

(c) part is the correct option

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