Question

The heat of melting of ice at 1 atmosphere pressure and 0°C is 1.4363 kcal/mol. The volume of ice is 0.0196 liter and the volume of the water is 0.18 liter

Answer 1

Answer:

Since heat is absorbed here at constant pressure so ΔH=1440 calories

ΔU can be calculated by using the formula  ΔU=ΔH−PΔV

P=1atm, ΔV=0.0196L−0.180L=0.0016L

P ΔV=1∗0.0016=0.0016Latm=0.0016∗24.217calories. (1Latm=24.217 calories)

So ΔU=1440cal−0.0016∗24.217cal≈1439.96calories .There is negligible work done here.

so you can write  ΔH≈ΔU.