Question

The heat of neutralisation of a strong base and a strong acid is 13.7 kcal. The heat released when 0.7 mole HBr
solution is added to 0.35 mole of KOH is

A)5.425 kcal

B)13.7 kcal
C)4.795 kcal
D 8.795 kcal​

Answer 1

Explanation:

ANSWER

1 mole

HCl

+

1 mole

NaOH

→NaCl+H

2

O ΔH=−13.7 Kcal

0.25 mole

HCl

+

0.6 mole

NaOH

→NaCl+H

2

O

Here HCl is the limiting reagent.

0 0.6−0.25 0.25mole

Then, release energy =13.7×0.25=3.425 Kcal