Question

The heat of neutralisation of HCl by NaOH is –55.9 kJ/mole.The energy of dissociation of HCN is :
$(HCN + OH^- \rightarrow CN^- + H_2O; \Delta H = -12.1 kJ)$
(a) 43.8 kJ
(b) – 43.8 kJ
(c) – 68 kJ
(d) 68 kJ

Answer 1

This question is incomplete add to question that if the heat of neutralisation of HCN by NaOH is -12.1kJ/mol... Or any other valur if u want.....

Because without known the value of the heat of neutralisation of HCN we can't find....

After that answer is part (b) -43.8kJ