Question

The heat of neutralization of four acids P Q R S are -13.7 - 9.4 - 11.2 - 12.4 kilo calorie respectively when they are neutralized by a common base the acidic character or base the order

Answer 1

Hey dear,

● Answer -
Acidic character P > S > R > Q

● Heat of neutralisation -
- The enthalpy of neutralization is the change in enthalpy that occurs when one equivalent of an acid and one equivalent of a base undergo a neutralization reaction to form water and a salt.
- Heat of neutralization decreases with decrease in strength of acid.

● Comparison -
First let's convert the given values to kJ -
P => ∆Hn = -13.7 kcal = -57.54 kJ
Q => ∆Hn = -9.4 kcal = -39.48 kJ
R => ∆Hn = -11.2 kcal = -47.04 kJ
S => ∆Hn = -12.4 kcal = -52.08 kJ

From the given data, acidic character in descending order is given by -
P > S > R > Q

Hope this helps...

Answer 2

"Heat of neutralization is the change in enthalpy which occurs when 1 equivalent of an acid and 1 equivalent of base undergoes neutralization to form salt and water

The heat of neutralization decreases with decrease in strength of acid.

Compare the heat of neutralization value of four acids

(Convert kcal to kJ multiply by 4.2)

For acid P, $\Delta { H }_{ n } = -13.7 kcal = -57.54 kJ$

For acid Q,$\Delta { H }_{ n } = -9.4 kcal = -39.48 kJ$

For acid R, $\Delta { H }_{ n } = -11.2 kcal = -47.04 kJ$

For acid S, $\Delta { H }_{ n } = -12.4 kcal = -52.08 kJ$

From the given values, the decrease in order of acidic character is P > S > R > Q"