Science, asked by ann203, 7 months ago

The heat released duriorixin of mul of 0.1
MH SO, with 50 mar 0.2 KOH is -
(1) 57.3 x 10') (2) 573)
(3) 5.73 x 10 (3 x 10)​

Answers

Answered by sutapabanerjee2017
1

Answer:

The total concentration of H2SO4 will be one-fifth of that of the NaOH. Also, their volumes will be equal as well that makes H2SO4, a limiting reactant to the solution. When 50cm3 of 0.2N H2SO4 is mixed with 50cm3 of 1N KOH heat liberated is 573 J.

Explanation:

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