Physics, asked by Teenavinod20, 1 month ago

the heat required convert 0.01 kg of ice at -20°C to Steam 100°C. (specific heat of ice = 2000 J/kg , latent heat of ice 335 x10 ³J/Kg and latent heat of steam= 2262×10 ³ J /kg)​

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Answered by DakshGamer134
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