The heater has a resistance of 3ohm The voltage source has an emf of 12v and an internal resistance of 1ohm at what rate does the voltage source apply energy to heater
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Energy is supplied to heater at the rate of - 27 W
Energy supplied to heater is equivalent to the power dissipated by heater.
Thus, power dissipated by the heater will be calculated by the formula -
P = I²R.
Current will be calculated by the formula -
V = IR
Here, p denotes power, I denotes current, r represents resistance, and V denotes voltage.
Total resistance of heater will be sum of external resistance and internal resistance.
Thus, R' = 3+1 ohm
R' = 4 ohm.
Now, calculating current -
(Total resistance will be considered here)
I = V/R
I = 12/4
I = 3 ampere.
Hence, power dissipated will be -
(Resistance of heater will be considered here)
P = 3²*3
P = 27 Watt
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