Physics, asked by Surgeon, 11 months ago

The heater has a resistance of 3ohm The voltage source has an emf of 12v and an internal resistance of 1ohm at what rate does the voltage source apply energy to heater

Answers

Answered by dakshrajput25
1

Answer:

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Answered by Anonymous
4

Energy is supplied to heater at the rate of - 27 W

Energy supplied to heater is equivalent to the power dissipated by heater.

Thus, power dissipated by the heater will be calculated by the formula -

P = I²R.

Current will be calculated by the formula -

V = IR

Here, p denotes power, I denotes current, r represents resistance, and V denotes voltage.

Total resistance of heater will be sum of external resistance and internal resistance.

Thus, R' = 3+1 ohm

R' = 4 ohm.

Now, calculating current -

(Total resistance will be considered here)

I = V/R

I = 12/4

I = 3 ampere.

Hence, power dissipated will be -

(Resistance of heater will be considered here)

P = 3²*3

P = 27 Watt

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