Question

The heating element connected to 230V
draws a current of 5A. Determine the
amount of heat dissipated in 1 hour
(J = 4.2 J/cal.).
​

Answer 1

Answer:

P=IV

P=5×230

P=1150 watt

The energy E=PT

E=1150×1

E=1150wh

=1.150kwh

Answer 2

Explanation:

Given that,

Voltage, V = 230 V

Current drawn, I = 5 A

We need to find the heat dissipated in 1 hour, t = 3600 s

The formula for the heat dissipated is given by :

$Q=I^2Rt$............(1)

R is the resistance of the heating element. R can be calculated using Ohm's law as :

$R=\dfrac{V}{I}$

$R=\dfrac{230}{5}$

R = 46 ohms

Put the values in equation (1) as :

$Q=(5)^2\times 46\times 3600$

Q = 4140000 Joules

So, the amount of heat dissipated in 1 hour is 4140000 Joules. Hence, this is the required solution.