Question

The heating element connected to 230V draws a current of 5A . Determine the amount of heat dissipated in 1 hour (J =4.2J/cal.

Answer 1

Answer:

1.15 Joule

0.238 Calorie

Explanation:

The heating element connected to 230V draws a current of 5A

I = V/R

R = V/I

=> R = 230/5 = 46 Ω

Heat Dissipated = I²Rt

= 5² * (46) * 1

= 1150 Wh

= 1.15 Kwh

= 1.15 Joule

4.2 Joule = 1 Calorie

=> 1.15 Joule = 1/4.2 Calorie

=> 1.15 Joule =  0.238 Calorie

Answer 2

Answer:

the given ans is true. so don't confused