Chemistry, asked by winkle36, 1 year ago

the heating of benzyl methyl ether with HI produces majorly
1)benzyl iodide and methanol
2)benzyl alcohol and iodomethane
3)benzyl alcohol and methanol
4)benzyl iodide and methane ​

Answers

Answered by ravi9848267328
1

i guess  it is benzyl alcohol and iodomethane

Answered by orangesquirrel
2

Answer: The correct answer is (2) benzyl alcohol and iodomethane.

Explanation:

Acidic cleavage takes place in case of ethers in the presence of a strong acid which is HI.

This strong acid protonates the oxygen molecule of the ether and enhances its elimination, i.e. in terms of leaving the group.

Next, the iodide ion reacts with the carbon atom to generate the resultant products.

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