The heaviest snake ever found had a mass of 227 kg and measured 8.45 m in length. Suppose a sample of a gas with an initial internal energy of 42.0 kJ performs an amount of work equal to that needed to lift the snake to a height equal to its length. If 4.00 kJ of energy is transferred to the gas by heat during the lifting process, what will be the final internal energy of the gas?
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ellydude88 said: 1. (4.186 * 10 ^3) (.180kg) (17) = (2.09 x 10 ^ 3)(.112kg)(15) I am unaware of how to account for the melted and remaining ice. Do i just do like a mass initial and final? When the tea cools from its initial temperature to 15C, how much energy is released? How much ice can be melted and then warmed to 15C by that amount of energy? 2. (227 kg) * (8.45 m) * (9.81) = 18, 817 J I really don't think im anywhere close to the right answer. The gas (a) does some work and (b) has heat flow into it. What's the net change in internal energy? What's the final internal energy?
Source https://www.physicsforums.com/threads/specific-heat-capacity-and-change-in-internal-energy.171418/
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