The height above the surface of earth at which the gravitational field intensity is reduced
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Answer:
This occurs at a distance of 7.3×106 m from the centre of the Earth (which is 900 km from the surface).
Explanation:
Are we okay to start from the field equation for the Earth's gravitational field?
g=GMr2 where M is the mass of the Earth.
What you do now, is change the subject of this equation so it solves for r:
r=√GMg
Plug in the numbers, and you have it!
r=√(6.67×10−11)(5.98×1024)7.5
= 7.3×106 m
(By the way, since this value is from the centre of the Earth, and the radius of the Earth is 6.4×106 m, we are looking at a point only 900 000 m (900 km) above the surface of the Earth.)
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