Question

the height above the surface of the earth at which the gravitational field intensity reduces to 1% of of its which on the surface of the Earth is

Answer 1

let the height be H
given,
   g' =1%of g
       =g/100
from      g' =g(1-2H/r)
        g/100=g(1-2H/r)
               1=100-200H/r
      200H/r=99
              H=99r/200