The height and diameter of a right circular cylinder are equal.The cylinder is
surmounted by a hemispherical lid of radius 3 inch, then total area of the surface of
the model is :
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Step-by-step explanation:
Since the lid is of radius 3inch, diameter of the cylinder =6inch.
=> height of the cylinder =6inch.
Surface area of the modal =
Curved surface area of hemispherical part + Curved surface area if the
cylinderical part.
Curved surface area of a cylinder =2πrh where r is the radius and h is the height.
Curved Surface Area of a hemisphere of radius 'r' =2πr2
Hence, surface area of the modal =(2π×32)+(2π×3×6)=54πm2=69.7 sq inch.
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