Math, asked by piyushghorla, 2 months ago

The height and diameter of a right circular cylinder are equal.The cylinder is
surmounted by a hemispherical lid of radius 3 inch, then total area of the surface of
the model is :​

Answers

Answered by pravinbachhao
0

Step-by-step explanation:

Since the lid is of radius 3inch, diameter of the cylinder =6inch.

=> height of the cylinder =6inch.

Surface area of the modal  =

Curved surface area of  hemispherical part + Curved surface area if the

cylinderical part.

Curved surface area of a cylinder =2πrh  where r is the radius and h is the height.

Curved Surface Area of a hemisphere of radius 'r' =2πr2

Hence, surface area of the modal =(2π×32)+(2π×3×6)=54πm2=69.7 sq inch.

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