Question

The height and radius of a cylindrical vessel are 10 cm and 28 cm respectively. Find the capacity of the vessel in litres.

Answer 1

Given

We have given height of the cylindrical vessel which is 10cm.

Radius of Cylindrical vessel = 28cm

To Find

We have to find the capacity of the vessel.

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Since, height and radius is given and have to find the capacity of the vessel.It means we have to find the volume.

➛Volume is the capacity or the density or amount of material a 3d object can have in it.

So,it is clearly we have to find the volume of the

vessel.

Since,vessel is in the shape of the Cyclinder so,we apply formula for volume of the cylinder.

➛Volume of Cyclinder= πr²h

➛Volume of Cylindrical vessel = πr²h

➛Volume of Cylindrical vessel= 22/7(28)²×10

➛Volume of Cylindrical vessel= 22/7×784×10

➛Volume of Cylindrical vessel= 22×112×10

➛Volume of Cylindrical vessel= 24640cm³.

Since, 1cm³= 1000 litres

So, 24640cm³= 24640÷1000

=> 24.64 ℓitres

∴The capacity of the vessel is 24.64 litres

Answer 2

Given :

• Height of Cylindrical vessel = 10cm
• Radius of Cylindrical vessel = 28cm

To Find :

• Capacity (volume) of Cylindrical vessel in litres.

Solution :

✰ As we know that, Volume of Cylinder is given by πr²h . So we will simply put the given values in the formula to find the volume of the Cylinder and in the Question it is asked that we have to given the volume in litres , so we will change the original volume to litres.

⠀

⠀⠀⟼⠀⠀Volume = πr²h

⠀⠀⟼⠀⠀Volume = 22/7 × (28)² × 10

⠀⠀⟼⠀⠀Volume = 22/7 × 28 × 28 × 10

⠀⠀⟼⠀⠀Volume = 22 × 4 × 28 × 10

⠀⠀⟼⠀⠀Volume = 88 × 28 × 10

⠀⠀⟼⠀⠀Volume = 88 × 280

⠀⠀⟼⠀⠀Volume = 24640cm³

⠀

Now,

⠀⠀⠀⠀ ➟⠀⠀⠀1cm³ = 1000 litres

⠀⠀⠀⠀ ➟ ⠀⠀24640cm³ = 24640/1000

⠀⠀⠀⠀ ➟⠀⠀ 24640cm³ = 24.64 litres

Thus Volume of Cylindrical vessel is 24.64 litres

________________

$\small\boxed{\begin{array}{cc}\large \red{\boxed{\sf\dag \: \blue{\underline \green{Formulae \: Related \: to \: Cylinder :}}}} \\ \\ \bigstar \: \sf Area\:of\:Base\:and\:top = \pi r^2 \\ \\\bigstar \: \sf Curved \: Surface \: Area =2 \pi rh \\ \\ \bigstar \: \sf Total \: Surface \: Area = 2 \pi r(h + r) \\ \\ \bigstar \: \sf Volume=\pi r^2h \end{array}}$