The height and radius of a solid cylinder are 15cm and 3 cm respectively two equal cones each of radius 3cm and height 4 cm are cut off one from each circular end of the cylinder find the surface area of remaining solid
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Answer:
The area of the remaining solid = 282.6 + 94.2 = 376.80 cm²
Step-by-step explanation:
Both the cylinder and the cones have the same radius.
So, what's left when the cones are cut out is the curved surface area of the cones.
The area of the cylinder will be the curved surface area of the cones plus the curved surface area of the cylinder.
The curved surface area of the cone = πrl
l = slant = √(h² + r²) = √25 = 5 cm
The curved surface area = 5 × 3 × 3.14 = 47.1 cm²
We have two cones so the total area of the conical parts = 2 × 47.1 = 94.2 cm²
The curved surface area of the cylindrical part is:
= 2πrh = 2 × 3.14 × 3 × 15 = 282.6 cm²
The area of the remaining solid = 282.6 + 94.2 = 376.80 cm²
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