the height and radius of base of cone each is increased by 100 %.how much is the volume of the cone then increased by
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Step-by-step explanation:
Saying something “increased by 100%” is same as saying it “became 2 times” of what it was.
So, if for a cone, radius and height are increased by 100%, then we can say that if original radius was R and height was H, then:
new radius = 2R and new height = 2H.
Now, volume (V) of a cone is given by the formula:
V = 1/3* π*(radius)^2 * (height)
So, in 1st case,
V1 = 1/3* π* (R)^2 * (H)
while in 2nd case
V2 = 1/3* π* (2R)^2 * (2H)
Hence, V2 = 8*[1/3* π* (R)^2 * (H)]
Hence, V2 = 8*(V1)
Thus, when radius and height of a cone are increased by 100%, volume becomes 8 times which is same as saying volume increases by 700%
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