The height and slant height of a conical vessel are 8 cm and 10cm respectively. Then the capacity of the vessel is _____ cu.cm.
a) 103.44
b) 401.33
c) 310.44
d) 301.71
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Given :
A conical vessel height, (h) = 8 cm
A conical vessel slant height, (l) = 10 cm
Explanation :
As we know that formula of the volume of cone:
Volume = 1/3πr²h [cubic unit]
According to the question :
Using formula of the slant height for get radius of cone ;
Slant height,(l) = √(r)² + (h)²
➝ (l)² = (r)² + (h)²
➝ (10)² = (r)² + (8)²
➝ 100 = r² + 64
➝ r² = 100 - 64
➝ r² = 36
➝ r = √36
➝ r = 6 cm
Now,
➝ Volume of cone = 1/3πr²h
➝ Volume of cone = 1/3 × 22/7 × 6 × 6 × 8
➝ Volume of cone = 1/3 × 22/7 × 6 × 6 × 8
➝ Volume of cone = 22 × 288/21
➝ Volume of cone = 6336/21
➝ Volume of cone = 301.71 cm³
As we know that, 1cm³ = 0.001litres
➝ (301.71 × 0.001) litres
➝ 0.30171 litres .
Thus,
The capacity of conical vessel having 0.30171 litters .
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