The height and the base of ∆ABC and ∆PQR are equal. FindA(∆ABC)
upon A(∆PQR) .
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height of both triangle be X
base of both triangle be y
area of ∆ABC = 1/2bh
area of ∆PQR = 1/2bh
area of ∆ABC =1/2yx
aear of ∆PQR =1/2yx
Therefore their raito will be 1:1
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