Physics, asked by pruthapatel0911, 8 months ago

The height and the distance x along the
horizontal plane of a projectile on a cetain
plane (with no surrounding atmosphere) are
given by y = 8t - 5t2 metre and x = 6t
metre, where t is in second. The velocity
with which the projectile is projected, is :-
(1) 14 ms-1
(2) 10 ms-1
(3) 8 ms-1
(4) 6 ms-1​

Answers

Answered by Anonymous
1

Answer:

Question

The height and the distance x along the

horizontal plane of a projectile on a cetain

plane (with no surrounding atmosphere) are

given by y = 8t - 5t2 metre and x = 6t

metre, where t is in second. The velocity

with which the projectile is projected, is :-

Answer :

option \: 2 \: 10 \: ms \:  - 1

x=6t,ux=dtdx=6</p><p></p><p>y=8t−5t2,vy=dtdy=8−10t</p><p></p><p>vy(t=0)=8ms−1</p><p></p><p>u=ux2+uy2=62+82=10ms−1</p><p></p><p>

Explanation:

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