Question

The height at which the acceleration due to
gravity decreases by 36% of its value on the
surface of the earth.
(The radius of earth is R).
(a)R/6
(b)R/4
(C)R/2
(d)2R/3​

Answer 1

Answer:

At what height from the surface of earth will the value of g be reduced by 36% from the value on the surface? Take radius of earth R=6400km. Solution : Since the acceleration due to gravity reduces by 36% the value of acceleration due to gravity there is 100-36=64%.

Answer 2

Answer:Since the acceleration due to gravity reduces by 36% the value of acceleration due to gravity there is 100−36=64%.

It means g'=64100g. If h is the height of location above the surface of earth then

g'=gR2(R+h)2

or 64100g=gR2(R+h2)2

810=RR+h or 8R+8h=10R

⇒h=2R8=R4=6.4×1064=1.6×106m