Question

The height at which the acceleration due to gravity becomes 9/g (where g is the acceleration due to gravity on the surface of the earth )in terms of R ,the radius of the earth is.................. option a) 2R. B)R/square root of 2. C) R/2 D) √2/R. plzzzzz very urgent

Answer 1

use formula
g'=g/(1+h/R)^2

g/9 =g/(1+h/R)^2

1/9=1/(1+h/R)^2

9=(1+h/R)^2

( 3)^2=(1+h/R)^2

3=1+h/R

h/R=2

h=2R
hence option (a) is correct

Answer 2

g/9 =g/(1+h/R)^2

1/9=1/(1+h/R)^2

9=(1+h/R)^2

( 3)^2=(1+h/R)^2

3=1+h/R

h/R=2

h=2option (a) is correct