Question

The height h in feet if a projectile launched vertically upward from the top of a 96 ft tall tower when t=0 is given by h=38+88t-16t^2

Answer 1

Step-by-step explanation:

given,

h= 38+88t-16t²

when t = 0 , h= 38 ft

=> projectile lunching time counted when it reached at 38 ft height from tower.

velocity of projectile

v = dh/dt =( 88-32t )

velocity at t= 0

88

acceleration

dv/dt= -32

=> the projectile acceleration is constant and in opposite direction of projection.