The height h, in feet, of a projectile t seconds after launch is modeled by the equation h = 32t – 16t2. How long after launch does the projectile return to the ground?
2 seconds
4 seconds
14 seconds
16 seconds
Answers
Answered by
4
Answer:
2 seconds
Step-by-step explanation:
given
h=32t-16t²
for t=1
h=32(1)-16(1)=16feet
for t=2
h=32(2)-16(4)=64-64=0
therefore after 2 seconds of it's flight it will return to the ground.
hence answer is 2 seconds.
Answered by
1
Answer:
therefore after 2 seconds of it's flight it will return to the ground. hence answer is 2 seconds.
Similar questions