Question

the height h in m of an object very with time t in seconds as h=10t-5t^2.then find maximum height attained by the object in m​

Answer 1

Answer:

dh/dt = 10 - 10td2h/dt2 = - 10 only macimadh/dt = 0 => t = 1 sec.hmax = 101 - 512hmax = 5 meter.

Explanation:

Answer 2

Answer:

here is the answer

Explanation:

Solution: From 3rd equation of motion

v2

= u2

+ 2as

v = 0, a = -g

∴ 02

= u2

+ 2(-g)s

2gs = u2

s =

u2

2g